Chapter 12: MATRICES
Introduction
Matrices are rectangular arrays of numbers that provide a powerful framework for representing and solving systems of linear equations, performing linear transformations, and organizing data. This summary covers matrix structure, operations, multiplication, inverses, and solving simultaneous equations.
Matrix Structure
Definition
A matrix is a rectangular array of numbers arranged in rows and columns. A matrix with $m$ rows and $n$ columns is called an $m \times n$ matrix (read "m by n").
$$ A = \begin{pmatrix} a_{11} & a_{12} & \cdots & a_{1n}\\ a_{21} & a_{22} & \cdots & a_{2n}\\ \vdots & \vdots & \ddots & \vdots\\ a_{m1} & a_{m2} & \cdots & a_{mn} \end{pmatrix} $$
Notation
- $a_{ij}$ denotes the element in the $i$th row and $j$th column.
- Matrices are often denoted by capital letters: $A$, $B$, $C$, etc.
- The order (or dimension) of a matrix is $m \times n$.
Special Types of Matrices
| Type | Description |
|---|---|
| Row matrix | $1 \times n$ (single row) |
| Column matrix | $m \times 1$ (single column) |
| Square matrix | $m=n$ (same number of rows and columns) |
| Zero matrix ($0$) | All entries are zero |
| Identity matrix ($I_n$) | Square matrix with $1$s on diagonal, $0$s elsewhere |
| Diagonal matrix | Non-zero entries only on main diagonal |
| Triangular matrix | All entries above or below diagonal are zero |
Examples
- $A= \begin{pmatrix} 2&-1&0\\ 3&4&5 \end{pmatrix}$ is a $2\times3$ matrix.
- $B= \begin{pmatrix} 1&2\\ 3&4 \end{pmatrix}$ is a $2\times2$ square matrix.
- $I_3= \begin{pmatrix} 1&0&0\\ 0&1&0\\ 0&0&1 \end{pmatrix}$ is the $3\times3$ identity matrix.
- $C= \begin{pmatrix} 4&0&0\\ 0&-2&0\\ 0&0&1 \end{pmatrix}$ is a diagonal matrix.
- $D= \begin{pmatrix} 1&2&3\\ 0&4&5\\ 0&0&6 \end{pmatrix}$ is an upper triangular matrix.
Matrix Operations and Definitions
Equality of Matrices
Two matrices $A$ and $B$ are equal if and only if:
- They have the same order ($m\times n$).
- Corresponding entries are equal: $a_{ij}=b_{ij}$ for all $i,j$.
Addition and Subtraction
Matrices can be added or subtracted only if they have the same order. Addition is performed element-wise:
$$ (A+B)_{ij}=a_{ij}+b_{ij} $$
Similarly, $$ (A-B)_{ij}=a_{ij}-b_{ij} $$
Properties of Matrix Addition
- Commutative: $A+B=B+A$
- Associative: $(A+B)+C=A+(B+C)$
- Identity: $A+0=A$
- Inverse: $A+(-A)=0$
Scalar Multiplication
Multiplying a matrix by a scalar $k$ multiplies every entry:
$$ (kA)_{ij}=k\cdot a_{ij} $$
Examples
-
Let
$$
A=\begin{pmatrix}1&2\\3&4\end{pmatrix},
B=\begin{pmatrix}5&6\\7&8\end{pmatrix}
$$
$$ A+B= \begin{pmatrix} 6&8\\ 10&12 \end{pmatrix} $$
$$ A-B= \begin{pmatrix} -4&-4\\ -4&-4 \end{pmatrix} $$
$$ 3A= \begin{pmatrix} 3&6\\ 9&12 \end{pmatrix} $$ - If $$ A=\begin{pmatrix}1&0\\-1&2\end{pmatrix}, B=\begin{pmatrix}2&1\\0&3\end{pmatrix} $$ Find $2A-B$. $$ 2A= \begin{pmatrix} 2&0\\ -2&4 \end{pmatrix} $$ $$ 2A-B= \begin{pmatrix} 0&-1\\ -2&1 \end{pmatrix} $$
Matrix Multiplication
Condition for Multiplication
Two matrices $A$ ($m\times n$) and $B$ ($p\times q$) can be multiplied if and only if $n=p$. The product $AB$ has order $m\times q$.
Definition
If $A$ is $m\times n$ and $B$ is $n\times p$, then $C=AB$ is $m\times p$ with entries:
$$ c_{ij}=\sum_{k=1}^{n}a_{ik}b_{kj} $$
$c_{ij}$ is the dot product of the $i$th row of $A$ and the $j$th column of $B$.
Properties of Matrix Multiplication
- Not commutative: $AB\neq BA$
- Associative: $(AB)C=A(BC)$
- Distributive: $A(B+C)=AB+AC$
- Identity: $AI_n=A$
- Zero: $A\cdot0=0$
Examples
- $$ A= \begin{pmatrix} 1&2\\ 3&4 \end{pmatrix}, B= \begin{pmatrix} 2&0\\ 1&3 \end{pmatrix} $$ $$ AB= \begin{pmatrix} 4&6\\ 10&12 \end{pmatrix} $$
- $$ A= \begin{pmatrix} 1&2&3\\ 4&5&6 \end{pmatrix}, B= \begin{pmatrix} 7&8\\ 9&10\\ 11&12 \end{pmatrix} $$ $$ AB= \begin{pmatrix} 58&64\\ 139&154 \end{pmatrix} $$
- $$ A= \begin{pmatrix} 0&1\\ 0&0 \end{pmatrix}, B= \begin{pmatrix} 0&0\\ 1&0 \end{pmatrix} $$ $$ AB= \begin{pmatrix} 1&0\\ 0&0 \end{pmatrix} $$ $$ BA= \begin{pmatrix} 0&0\\ 0&1 \end{pmatrix} $$ Therefore, $$AB\neq BA$$
The Inverse of a $2 \times 2$ Matrix
Definition
For a square matrix $A$, if there exists a matrix $A^{-1}$ such that:
$$ AA^{-1}=A^{-1}A=I $$
then $A^{-1}$ is the inverse of $A$. A matrix that has an inverse is called invertible (or non-singular).
Inverse of a $2 \times 2$ Matrix
For $$ A= \begin{pmatrix} a&b\\ c&d \end{pmatrix} $$
$$ A^{-1} = \frac{1}{ad-bc} \begin{pmatrix} d&-b\\ -c&a \end{pmatrix} $$
provided that $\det(A)=ad-bc\neq0$.
The Determinant
The quantity $\det(A)=ad-bc$ is called the determinant of the $2\times2$ matrix $A$.
- If $\det(A)\neq0$, $A$ is invertible.
- If $\det(A)=0$, $A$ is singular (no inverse).
Properties of Inverses
- $(A^{-1})^{-1}=A$
- $(AB)^{-1}=B^{-1}A^{-1}$
- $(kA)^{-1}=\frac{1}{k}A^{-1}$
- $\det(A^{-1})=\frac{1}{\det(A)}$
Examples
-
Find the inverse of $$ A= \begin{pmatrix} 2&3\\ 1&4 \end{pmatrix} $$
$$ \det(A)=2\cdot4-3\cdot1=8-3=5\neq0 $$
$$ A^{-1} = \frac15 \begin{pmatrix} 4&-3\\ -1&2 \end{pmatrix} $$
$$ = \begin{pmatrix} \frac45&-\frac35\\ -\frac15&\frac25 \end{pmatrix} $$
Check: $$ AA^{-1} = \begin{pmatrix} 1&0\\ 0&1 \end{pmatrix} $$
-
Find the inverse of $$ B= \begin{pmatrix} 1&2\\ 2&4 \end{pmatrix} $$
$$ \det(B)=1\cdot4-2\cdot2=0 $$
$B$ is singular, so no inverse exists.
-
Find the inverse of $$ C= \begin{pmatrix} 3&-1\\ -2&1 \end{pmatrix} $$
$$ \det(C)=3\cdot1-(-1)(-2)=1 $$
$$ C^{-1} = \begin{pmatrix} 1&1\\ 2&3 \end{pmatrix} $$
-
If $$ A= \begin{pmatrix} 2&5\\ 1&3 \end{pmatrix} $$ verify that $$ A^{-1} = \begin{pmatrix} 3&-5\\ -1&2 \end{pmatrix} $$
$$ AA^{-1} = \begin{pmatrix} 1&0\\ 0&1 \end{pmatrix} $$
Simultaneous Linear Equations
Matrix Representation
A system of linear equations can be written as:
$$ AX=B $$
where:
$$ A= \begin{pmatrix} a_{11}&a_{12}&\cdots&a_{1n}\\ \vdots&&&\vdots\\ a_{m1}&a_{m2}&\cdots&a_{mn} \end{pmatrix} $$
$$ X= \begin{pmatrix} x_1\\ x_2\\ \vdots\\ x_n \end{pmatrix} $$
and $$ B= \begin{pmatrix} b_1\\ b_2\\ \vdots\\ b_m \end{pmatrix} $$
Solving $2\times2$ Systems Using Inverse
For an invertible matrix $A$:
$$ X=A^{-1}B $$
Method
- Write the system in matrix form $AX=B$.
- Find $A^{-1}$.
- Multiply $A^{-1}B$.
- The solution is obtained from $X$.
Examples
-
Solve $$ \begin{cases} 2x+3y=5\\ x+4y=6 \end{cases} $$ using matrices.
$$ A= \begin{pmatrix} 2&3\\ 1&4 \end{pmatrix}, \quad X= \begin{pmatrix} x\\y \end{pmatrix}, \quad B= \begin{pmatrix} 5\\6 \end{pmatrix} $$
$$ A^{-1} = \frac15 \begin{pmatrix} 4&-3\\ -1&2 \end{pmatrix} $$
$$ X=A^{-1}B $$
$$ = \begin{pmatrix} \frac45&-\frac35\\ -\frac15&\frac25 \end{pmatrix} \begin{pmatrix} 5\\6 \end{pmatrix} $$
$$ = \begin{pmatrix} \frac45(5)-\frac35(6)\\ -\frac15(5)+\frac25(6) \end{pmatrix} $$
$$ = \begin{pmatrix} \frac25\\ \frac75 \end{pmatrix} $$
Solution: $x=\frac25,\quad y=\frac75$
-
Solve $$ \begin{cases} 3x-y=8\\ -2x+y=-5 \end{cases} $$
$$ A= \begin{pmatrix} 3&-1\\ -2&1 \end{pmatrix} $$
$$ \det(A)=3(1)-(-1)(-2)=1 $$
$$ A^{-1} = \begin{pmatrix} 1&1\\ 2&3 \end{pmatrix} $$
$$ X= \begin{pmatrix} 1&1\\ 2&3 \end{pmatrix} \begin{pmatrix} 8\\-5 \end{pmatrix} $$
$$ = \begin{pmatrix} 3\\1 \end{pmatrix} $$
Solution: $x=3,\quad y=1$
-
Solve $$ \begin{cases} 4x+2y=10\\ 2x+3y=9 \end{cases} $$
$$ A= \begin{pmatrix} 4&2\\ 2&3 \end{pmatrix} $$
$$ \det(A)=4(3)-2(2)=8 $$
$$ A^{-1} = \frac18 \begin{pmatrix} 3&-2\\ -2&4 \end{pmatrix} $$
$$ X= \frac18 \begin{pmatrix} 3&-2\\ -2&4 \end{pmatrix} \begin{pmatrix} 10\\9 \end{pmatrix} $$
$$ = \frac18 \begin{pmatrix} 12\\16 \end{pmatrix} = \begin{pmatrix} \frac32\\2 \end{pmatrix} $$
Solution: $x=\frac32,\quad y=2$
Inconsistent and Dependent Systems
- Inconsistent system (no solution): $\det(A)=0$ but equations contradict.
- Dependent system (infinite solutions): $\det(A)=0$ and equations are multiples.
Example: Inconsistent System
Solve: $$ \begin{cases} x+2y=3\\ 2x+4y=7 \end{cases} $$
$$ \det(A)=1(4)-2(2)=0 $$
The second equation gives:
$$ 2(x+2y)=7 $$
but
$$ 2(3)=7 $$
which is false.
No solution.
Example: Dependent System
Solve: $$ \begin{cases} x+2y=3\\ 2x+4y=6 \end{cases} $$
The second equation is twice the first equation.
Infinite solutions:
$$ x=3-2t,\qquad y=t $$
Solving $3 \times 3$ Systems (Extension)
For a $3\times3$ system, inverse methods can be used, but calculations are longer.
- Gaussian elimination
- Cramer's rule
- Adjugate matrix method
Example: $3\times3$ System
Solve: $$ \begin{cases} x+y+z=6\\ x-y+z=2\\ 2x+y-z=1 \end{cases} $$
Matrix form:
$$ A= \begin{pmatrix} 1&1&1\\ 1&-1&1\\ 2&1&-1 \end{pmatrix} $$
$$ B= \begin{pmatrix} 6\\2\\1 \end{pmatrix} $$
Using inverse:
$$ A^{-1} = \begin{pmatrix} 0&\frac12&\frac12\\ \frac34&-\frac34&0\\ \frac14&\frac14&-\frac12 \end{pmatrix} $$
$$ X=A^{-1}B $$
$$ = \begin{pmatrix} \frac32\\ 3\\ \frac32 \end{pmatrix} $$
Solution: $$ x=\frac32,\quad y=3,\quad z=\frac32 $$
Summary Table
| Concept | Key Points |
|---|---|
| Matrix order | $m\times n$ ($m$ rows, $n$ columns) |
| Addition/Subtraction | Same order, element-wise |
| Scalar multiplication | Multiply every entry by scalar |
| Matrix multiplication | $AB$ exists if columns of $A$ = rows of $B$ |
| Multiplication rule | $(AB)_{ij}=row_i(A)\cdot column_j(B)$ |
| Determinant | $\det(A)=ad-bc$ |
| Inverse | $A^{-1}=\frac1{\det(A)} \begin{pmatrix} d&-b\\ -c&a \end{pmatrix}$ |
| Solving $AX=B$ | $X=A^{-1}B$ |
| Singular matrix | $\det(A)=0$, no inverse |
| Inconsistent system | No solution |
| Dependent system | Infinite solutions |
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