Chapter 9: TRIGONOMETRIC FUNCTIONS
Chapter 9: TRIGONOMETRIC FUNCTIONS
Introduction
Trigonometric functions describe periodic phenomena such as waves, oscillations, and circular motion. This summary covers periodic behaviour, the sine, cosine, and tangent functions, trigonometric equations, identities, and solving equations in quadratic form.
Periodic Behaviour
Definition
A function $f(x)$ is periodic if there exists a positive constant $P$ (the period) such that:
$ f(x+P)=f(x) \quad \text{for all } x \text{ in the domain} $
The smallest such $P$ is the fundamental period.
Properties of Periodic Functions
- The graph repeats every $P$ units.
- If $f$ has period $P$, then $f(kx)$ has period $\frac{P}{|k|}$.
- The sum of periodic functions may not be periodic unless periods are commensurable.
Periods of Trigonometric Functions
| Function | Principal Period |
|---|---|
| $\sin x$, $\cos x$, $\csc x$, $\sec x$ | $2\pi$ |
| $\tan x$, $\cot x$ | $\pi$ |
Examples
- $\sin(2x)$ has period $ \frac{2\pi}{2}=\pi $
- $ \cos\left(\frac{x}{3}\right) $ has period $ \frac{2\pi}{1/3}=6\pi $
- $ \tan(4x) $ has period $ \frac{\pi}{4} $
- The function $ f(x)=\sin x+\sin(2x) $ is periodic with period $2\pi$ (least common multiple of $2\pi$ and $\pi$).
The Sine Function
Definition
$ y=\sin x $ is defined as the $y$-coordinate of the point on the unit circle at angle $x$ radians.
Key Properties
- Domain: $\mathbb{R}$ (all real numbers)
- Range: $[-1,1]$
- Period: $2\pi$
- Amplitude: $1$
- Odd function: $\sin(-x)=-\sin x$
- Zeros: $x=n\pi$ where $n\in\mathbb{Z}$
- Maximum: $1$ at $x=\frac{\pi}{2}+2n\pi$
- Minimum: $-1$ at $x=\frac{3\pi}{2}+2n\pi$
Graph of $y=\sin x$
Transformed Sine Function
For $ y=a\sin(bx-c)+d $ :
- Amplitude: $|a|$
- Period: $\frac{2\pi}{|b|}$
- Phase shift: $\frac{c}{b}$ (to the right if $c > 0$)
- Vertical shift: $d$
Examples
-
Find the amplitude, period, and phase shift of
$
y=3\sin(2x-\pi)
$.
Amplitude $=3$, Period $ \frac{2\pi}{2}=\pi $, Phase shift $ \frac{\pi}{2} $ to the right. -
Sketch
$
y=\sin\left(x-\frac{\pi}{2}\right)
$.
This is $\sin x$ shifted right by $ \frac{\pi}{2} $ (equivalent to $-\cos x$). -
Evaluate
$
\sin\frac{5\pi}{6}
$.
$ \frac{5\pi}{6}=150^\circ $, $ \sin\frac{5\pi}{6} = \sin\frac{\pi}{6} = \frac{1}{2} $
The Cosine Function
Definition
$y=\cos x$ is defined as the $x$-coordinate of the point on the unit circle at angle $x$ radians.
Key Properties
- Domain: $\mathbb{R}$
- Range: $[-1,1]$
- Period: $2\pi$
- Amplitude: $1$
- Even function: $\cos(-x)=\cos x$
- Zeros: $x=\frac{\pi}{2}+n\pi$
- Maximum: $1$ at $x=2n\pi$
- Minimum: $-1$ at $x=\pi+2n\pi$
Graph of $y=\cos x$
Relationship Between Sine and Cosine
$$ \sin x=\cos\left(x-\frac{\pi}{2}\right), \qquad \cos x=\sin\left(x+\frac{\pi}{2}\right) $$
Examples
-
Find the zeros of $y=2\cos(3x)$ on $[0,2\pi)$.
$\cos(3x)=0 \implies 3x=\frac{\pi}{2}+n\pi \implies x=\frac{\pi}{6}+\frac{n\pi}{3}$
For $n=0,1,2,3,4,5$: $$ x=\frac{\pi}{6}, \frac{\pi}{2}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{3\pi}{2}, \frac{11\pi}{6} $$
-
Evaluate $\cos\frac{4\pi}{3}$.
$\frac{4\pi}{3}=240^\circ$, reference angle $\frac{\pi}{3}$ (Quadrant III, cosine negative).
$$ \cos\frac{4\pi}{3} = -\cos\frac{\pi}{3} = -\frac12 $$
-
Find the maximum and minimum of $y=5-3\cos x$.
$$ \cos x\in[-1,1] $$ $$ 5-3\cos x \in [5-3(1),\,5-3(-1)] = [2,8] $$
Maximum $=8$, Minimum $=2$.
The Tangent Function
Definition
$$ \tan x=\frac{\sin x}{\cos x} $$
Key Properties
- Domain: $x\neq \frac{\pi}{2}+n\pi$ (where $\cos x=0$)
- Range: $\mathbb{R}$
- Period: $\pi$
- Odd function: $\tan(-x)=-\tan x$
- Zeros: $x=n\pi$
- Vertical asymptotes: $x=\frac{\pi}{2}+n\pi$
- Increasing on each interval $\left(-\frac{\pi}{2}+n\pi,\frac{\pi}{2}+n\pi\right)$
Graph of $y=\tan x$
Transformed Tangent Function
For $y=a\tan(bx-c)+d$:
- Period: $\frac{\pi}{|b|}$
- Phase shift: $\frac{c}{b}$
- Vertical shift: $d$
- Asymptotes at $bx-c=\frac{\pi}{2}+n\pi$
Examples
-
Find the period and asymptotes of $y=\tan(2x)$.
Period: $$ \frac{\pi}{2} $$
Asymptotes: $$ 2x=\frac{\pi}{2}+n\pi $$ $$ x=\frac{\pi}{4}+\frac{n\pi}{2} $$
-
Evaluate $\tan\frac{3\pi}{4}$.
$\frac{3\pi}{4}=135^\circ$ (Quadrant II, tangent negative).
Reference angle: $$ \frac{\pi}{4} $$ $$ \tan\frac{3\pi}{4} = -\tan\frac{\pi}{4} = -1 $$
-
Solve $\tan x=\sqrt3$ for $x\in[0,2\pi)$.
Reference angle: $$ \frac{\pi}{3} $$
Tangent is positive in Quadrants I and III:
$$ x=\frac{\pi}{3}, \qquad x=\frac{4\pi}{3} $$
Trigonometric Equations
General Solution Formulas
$$ \sin\theta=\sin\alpha \implies \theta=\alpha+2n\pi \quad\text{or}\quad \theta=\pi-\alpha+2n\pi $$
$$ \cos\theta=\cos\alpha \implies \theta=\pm\alpha+2n\pi $$
$$ \tan\theta=\tan\alpha \implies \theta=\alpha+n\pi $$
Solving Strategy
- Isolate the trigonometric function.
- Find the reference angle (principal value).
- Determine all quadrants where the function has the given sign.
- Write the general solution using periodicity.
- Find required solutions in the given interval.
Examples
-
Solve $\sin x=\frac{\sqrt3}{2}$ for $x\in[0,2\pi)$.
Reference angle: $$ \frac{\pi}{3} $$
Sine is positive in Quadrants I and II:
$$ x=\frac{\pi}{3}, \qquad x=\frac{2\pi}{3} $$
-
Solve $\cos x=-\frac12$ for $x\in\mathbb{R}$.
$$ x=\frac{2\pi}{3}+2n\pi $$ or $$ x=\frac{4\pi}{3}+2n\pi $$
-
Solve $\tan x=-1$ for $x\in[0,2\pi)$.
$$ x=\frac{3\pi}{4}, \qquad x=\frac{7\pi}{4} $$
-
Solve $2\sin x+1=0$ for $x\in[0,2\pi)$.
$$ \sin x=-\frac12 $$
$$ x=\frac{7\pi}{6}, \qquad x=\frac{11\pi}{6} $$
Trigonometric Relationships (Identities)
Fundamental Identities
$$ \sin^2 x + \cos^2 x = 1 $$ $$ 1 + \tan^2 x = \sec^2 x $$ $$ 1 + \cot^2 x = \csc^2 x $$Reciprocal Identities
$$ \csc x = \frac{1}{\sin x}, \quad \sec x = \frac{1}{\cos x}, \quad \cot x = \frac{1}{\tan x} $$Quotient Identities
$$ \tan x = \frac{\sin x}{\cos x}, \quad \cot x = \frac{\cos x}{\sin x} $$Even-Odd Identities
$$ \sin(-x) = -\sin x \quad \text{(odd)} $$ $$ \cos(-x) = \cos x \quad \text{(even)} $$ $$ \tan(-x) = -\tan x \quad \text{(odd)} $$Co-function Identities
$$ \sin\left(\frac{\pi}{2}-x\right)=\cos x,\quad \cos\left(\frac{\pi}{2}-x\right)=\sin x $$ $$ \tan\left(\frac{\pi}{2}-x\right)=\cot x $$Addition and Subtraction Formulas
$$ \sin(A+B)=\sin A\cos B+\cos A\sin B $$ $$ \sin(A-B)=\sin A\cos B-\cos A\sin B $$ $$ \cos(A+B)=\cos A\cos B-\sin A\sin B $$ $$ \cos(A-B)=\cos A\cos B+\sin A\sin B $$ $$ \tan(A+B)=\frac{\tan A+\tan B}{1-\tan A\tan B} $$ $$ \tan(A-B)=\frac{\tan A-\tan B}{1+\tan A\tan B} $$Double Angle Formulas
$$ \sin(2x)=2\sin x\cos x $$ $$ \cos(2x)=\cos^2 x-\sin^2 x =2\cos^2 x-1 =1-2\sin^2 x $$ $$ \tan(2x)=\frac{2\tan x}{1-\tan^2 x} $$Examples
-
Simplify $ \frac{\sin^2 x}{1-\cos x} $.
$ \frac{\sin^2 x}{1-\cos x} = \frac{1-\cos^2 x}{1-\cos x} = \frac{(1-\cos x)(1+\cos x)}{1-\cos x} = 1+\cos x $
-
Prove $ \tan x \sin x + \cos x = \sec x $.
LHS $ = \frac{\sin x}{\cos x}\cdot\sin x+\cos x = \frac{\sin^2 x}{\cos x}+\cos x = \frac{\sin^2 x+\cos^2 x}{\cos x} = \frac{1}{\cos x} = \sec x $
-
Find $ \cos 75^\circ $ exactly.
$ \cos 75^\circ = \cos(45^\circ+30^\circ) = \cos45^\circ\cos30^\circ - \sin45^\circ\sin30^\circ $
$ = \frac{\sqrt2}{2}\cdot\frac{\sqrt3}{2} - \frac{\sqrt2}{2}\cdot\frac12 = \frac{\sqrt6-\sqrt2}{4} $
-
Simplify $ \sin(2x)\cos x+\cos(2x)\sin x $.
Using the sine addition formula:
$ \sin(2x)\cos x+\cos(2x)\sin x = \sin(2x+x) = \sin(3x) $
Trigonometric Equations in Quadratic Form
Method
Equations of the form $a\sin^2 x+b\sin x+c=0$ (or with $\cos x$ or $\tan x$) are solved by:
- Substitute $u=\sin x$ (or $\cos x$, $\tan x$).
- Solve the quadratic $au^2+bu+c=0$.
- Back-substitute and solve for $x$.
- Check for extraneous solutions (especially when squaring or using $\tan$).
Examples
-
Solve $2\sin^2 x-\sin x-1=0$ for $x\in[0,2\pi)$.
Let $u=\sin x$:
$ 2u^2-u-1=0 $
$ (2u+1)(u-1)=0 \implies u=-\frac12 \text{ or } u=1 $
$ \sin x=-\frac12 \Rightarrow x=\frac{7\pi}{6},\frac{11\pi}{6} $
$ \sin x=1 \Rightarrow x=\frac{\pi}{2} $
Solutions: $ x=\frac{\pi}{2}, \frac{7\pi}{6}, \frac{11\pi}{6} $
-
Solve $2\cos^2 x-3\cos x+1=0$ for $x\in[0,2\pi)$.
Let $u=\cos x$:
$ 2u^2-3u+1=0 $
$ (2u-1)(u-1)=0 \implies u=\frac12 \text{ or } u=1 $
$ \cos x=\frac12 \Rightarrow x=\frac{\pi}{3},\frac{5\pi}{3} $
$ \cos x=1 \Rightarrow x=0 $
Solutions: $ x=0, \frac{\pi}{3}, \frac{5\pi}{3} $
-
Solve $\tan^2 x-3=0$ for $x\in[0,2\pi)$.
$ \tan^2 x=3 \Rightarrow \tan x=\pm\sqrt3 $
$ \tan x=\sqrt3 \Rightarrow x=\frac{\pi}{3}, \frac{4\pi}{3} $
$ \tan x=-\sqrt3 \Rightarrow x=\frac{2\pi}{3}, \frac{5\pi}{3} $
Solutions: $ x= \frac{\pi}{3}, \frac{2\pi}{3}, \frac{4\pi}{3}, \frac{5\pi}{3} $
-
Solve $\sin^2 x-\cos^2 x=0$ for $x\in[0,2\pi)$.
Using $ \cos^2 x=1-\sin^2 x $
$ \sin^2 x-(1-\sin^2 x)=0 $
$ 2\sin^2 x-1=0 \Rightarrow \sin^2 x=\frac12 \Rightarrow \sin x=\pm\frac{\sqrt2}{2} $
Solutions: $ x= \frac{\pi}{4}, \frac{3\pi}{4}, \frac{5\pi}{4}, \frac{7\pi}{4} $
-
Solve $3\sec^2 x-4=0$ for $x\in[0,2\pi)$.
$ \sec^2 x=\frac43 \Rightarrow \cos^2 x=\frac34 \Rightarrow \cos x=\pm\frac{\sqrt3}{2} $
$ \cos x=\frac{\sqrt3}{2} \Rightarrow x=\frac{\pi}{6}, \frac{11\pi}{6} $
$ \cos x=-\frac{\sqrt3}{2} \Rightarrow x=\frac{5\pi}{6}, \frac{7\pi}{6} $
Solutions: $ x= \frac{\pi}{6}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{11\pi}{6} $
Using Identities to Create Quadratic Form
Sometimes the equation needs to be rewritten using identities before substitution.
Example: Using $ \cos 2x $ Identity
Solve $ \cos 2x+\cos x=0 $ for $x\in[0,2\pi)$.
Using $ \cos 2x=2\cos^2 x-1 $:
$$ 2\cos^2 x-1+\cos x=0 \implies 2\cos^2 x+\cos x-1=0 $$Let $u=\cos x$:
$$ 2u^2+u-1=0 \implies (2u-1)(u+1)=0 $$ $$ u=\frac12 \quad\text{or}\quad u=-1 $$$ \cos x=\frac12 \Rightarrow x=\frac{\pi}{3}, \frac{5\pi}{3} $
$ \cos x=-1 \Rightarrow x=\pi $
Solutions: $ x= \frac{\pi}{3}, \pi, \frac{5\pi}{3} $
Summary Table
| Concept | Key Points |
|---|---|
| Periodicity | $\sin$, $\cos$ period $2\pi$; $\tan$ period $\pi$ |
| Sine | Domain $\mathbb{R}$, range $[-1,1]$, odd |
| Cosine | Domain $\mathbb{R}$, range $[-1,1]$, even |
| Tangent | Domain $x \neq \frac{\pi}{2}+n\pi$, range $\mathbb{R}$, odd |
| General solutions | $\sin\theta=\sin\alpha \Rightarrow \theta=\alpha+2n\pi$ or $\pi-\alpha+2n\pi$ |
| $\cos\theta=\cos\alpha \Rightarrow \theta=\pm\alpha+2n\pi$ | |
| $\tan\theta=\tan\alpha \Rightarrow \theta=\alpha+n\pi$ | |
| Pythagorean identities | $\sin^2\theta+\cos^2\theta=1$, $1+\tan^2\theta=\sec^2\theta$ |
| Double angle | $\sin2\theta=2\sin\theta\cos\theta$, $\cos2\theta=\cos^2\theta-\sin^2\theta$ |
| Quadratic equations | Substitute $u=\sin x$ (or $\cos x$, $\tan x$), solve, back-substitute |



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